Question

An object is moving with an initial velocity of 23 m/s. It is then subject to a constant acceleration of 3.5 m/s2 for 12 s. How far will it have traveled during the time of its acceleration?

Answer 1

528 m

Step-by-step explanation:

We can solve the problem by using the following suvat equation:

`s=ut+(1)/(2)at^2`

where

s is the displacement

u is the initial velocity

t is the time

a is the acceleration

In this problem,

u = 23 m/s

`a=3.5 m/s^2`

And substituting t = 12 s, we find the distance travelled:

`s=(23)(12)+(1)/(2)(3.5)(12)^2=528 m`