Question

If you had 1024 grams of tritium in 1895, how much would you have in 2018?

Answer 1

0.8994 grams of tritium

Step-by-step explanation:

Half life of tritium = 12.32 years

`t_(1/2)=\frac {ln\ 2}{k}`

Where, k is rate constant

So,

`k=\frac {ln\ 2}{t_(1/2)}`

`k=\frac {ln\ 2}{12.32}\ year^(-1)`

The rate constant, k = 0.0563 year⁻¹

Time = 1895 to 2018 = 124 years

Using integrated rate law for first order kinetics as:

`[A_t]=[A_0]e^(-kt)`

Where,

`[A_t]` is the concentration at time t

`[A_0]` is the initial concentration = 1024 grams

So,

`[A_t]=1024* e^(-0.0563* 125)=0.8994\ grams`

In 2018, we have 0.8994 grams of tritium.