Question

2. Find the slope of a line that contains the

points (0, -2), (3, 1).
3. Find the slope of a line that contains the
points (0.-2), (2.-8).

Answer 1

This picture

Explanation:

in the picture

Answer 2

The slope of a line that contains the points (0, -2), (3, 1) is 1 and points (0.-2), (2.-8) is -3

Solution:

2. For the first problem,

The points are
`(x_1,y_1) = (0,-2)` and
`(x_2,y_2) = (3,1)`

Let us assume that the slope is m.

We know the slope on a point
`=(y_(2)-y_(1))/(x_(2)-x_(1))`

Now substituting the value of the points we get,

`\text { Slope } m=(1-(-2))/(3-0)=(1+2)/(3)=(3)/(3)=1`

3. For the second problem,

The points are
`(x_1,y_1) = (0,-2)` and
`(x_2,y_2) = (2,-8)`

Let us assume that the slope is m1

We know the slope on a point
`=(y_(2)-y_(1))/(x_(2)-x_1)`

Now putting the value of the points we get,

`\text { Slope } m 1=(-8-(-2))/(2-0)=(-6)/(2)=(-3)`