Question

At what characteristic wavelength does a blackbody at room temperature radiate?

Answer 1

9.73154 × 10⁻⁶ m, infrared region

Step-by-step explanation:

Using Wien's displacement law which states that the temperature and the wavelength of the blackbody radiation are inversely proportional.

So,

λmax= b/T

Where,

λmax is the peak of wavelength

b is the Wien's displacement constant having value as
`2.9* 10^(-3)\  m K`

T is the Absolute Temperature in Kelvins . Room temperature = 298 K

So,

λmax= b/T =
`(2.9* 10^(-3))/(298)` = 9.73154 × 10⁻⁶ m

This wavelength corresponds to infrared region.