Question

Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: In a particular experiment, a 2.00 g sample of a CaO is reacted with excess water and 2.14 grams of Ca(OH)2 is recovered. What is the percentage yield of this experiment?

Answer 1

The answer to your question is: yield = 81 %

Step-by-step explanation:

Data

Calcium oxide mass = 2 g

Calcium hydroxide mass = 2.14 g

yield = ?

Process

Reaction

CaO + H₂O ⇒ Ca(OH)₂

MW CaO = 40 + 16 = 56 g

MW Ca(OH)₂ = 40 + 32 + 2 = 74 g

56 g of CaO ----------------- 74 g of Ca(OH)₂

2 g ---------------- x

x = (2 x 74)/ 56

x = 2.64 g of Ca(OH)₂

yield = experimental / theoretical x 100

yield = 2.14 / 2.64 x 100

yield = 81 %