Question

Write a quadratic equation with roots of 1/3 and −7/2.​

Answer 1

The answer would be, Y= (3x - 1) (2x + 7)

Explanation:

Answer 2

Quadratic equation with roots 1/3 and -7/2 is:

`6x^(2) + 19x - 7 = 0`

Explanation:

Roots of the equation are 1/3 and -7/2

Quadratic equation is of the form:

`ax^(2) +bx + c = o`

Now Sum of roots =
`(-b)/(a)`

Sum of roots =
`(1)/(3) + ((-7)/(2)) = (2 - 21)/(6) = (- 19)/(6) = (- b)/(a)`

∴ b = 19 and a = 6

Product of roots = c/a

Product of the roots =
`(1)/(3) * (-7)/(2) = (-7)/(6) = (c)/(a)`

∴ a = 6, b = 19 and c = -7

So the quadratic equation with roots 1/3 and -7/2 is:

`6x^(2) + 19x - 7 = 0`