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how much centripetal force is needed to make a body of mass 0.5 kg to move in a circle of radius 50 cm with a speed 3ms-1

User Doug Lee
by
4.7k points

2 Answers

6 votes

Answer:

Step-by-step explanation:

F = (mv^2)/r

= (0.5 × 3^2) / 50×10^-2

= 9N

User Enedil
by
4.9k points
1 vote

Answer:

9 N

Step-by-step explanation:

The centripetal force F is F = mrω^2 = (mv^2)/r where m is mass, r is radius of the curve, ω is angular velocity and v is tangential velocity.

In this case, m = 0.5kg, r = 0.5m, v = 3m/s

So F = [0.5kg(3m/s)^2]/0.5m = 9kg-m/s^2 which is 9N

User Chris McCord
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4.6k points