Question

a hockey player has an acceleration of -3.1 m/s ². How long does it take him to come to a complete stop from a speed of 13 m/s?

Answer 1

Step-by-step explanation:

a = (v-u) / t

-3.1 = -13/t

t = 4.19s

Answer 2

A hockey player has an acceleration of -3.1
`m/s^2` to complete at a speed of 13 m/s it takes him 4.2 seconds.

Step-by-step explanation:

Applying the 1 \mathrm{st} Equation of Motion

v = u + at

where v = Final Velocity

u = Initial Velocity

a = acceleration

t = time

Given-

v = 0 m/s (Complete stop)

u = +13 m/s

a = -3.1
`\mathrm{m} / \mathrm{s}^(2)` (negative shows deceleration)

Putting the Values

0 = 13 + (-3.1)t

or, 3.1t = 13

or, t=
`(130)/(31)`

or, t = 4.1935 seconds = 4.2 s