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Consult Interactive Solution 4.65 before beginning this problem. A toboggan slides down a hill and has a constant velocity. The angle of the hill is 6.00° with respect to the horizontal. What is the coefficient of kinetic friction between the surface of the hill and the toboggan

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Answer:


\mu_k=0.14

Step-by-step explanation:

It is given that,

The angle of the hill is 6.00° with respect to the horizontal. Let
\mu_k is the coefficient of kinetic friction between the surface of the hill and the toboggan.

A toboggan slides down a hill and has a constant velocity. On an inclined plane, force of friction will also act.

Force of friction,
f_k=mg\ sin\theta...........(1)

Normal force,
N=mg\ cos\theta............(2)

From equation (1) and (2) :


\mu_kmg\ cos\theta=mg\ sin\theta


\mu_k=tan\theta


\mu_k=tan(8)


\mu_k=0.14

So, the coefficient of kinetic friction between the surface of the hill and the toboggan is 0.14. Hence, this is the required solution.