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A frictionless piston–cylinder device contains 2.5 kg of nitrogen at 100 kPa and 250 K. Nitrogen is now compressed slowly according to the relation PV1.4 = constant until it reaches a final temperature of 450 K. Calculate the work input during this process. The gas constant for nitrogen is R = 0.2968 kJ/kg·K.

User Sulman
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2 Answers

4 votes

Answer:

The work input during this process is 371 kJ.

Step-by-step explanation:

For a polytropic process, as this one, work can be computed from the formula


W=(mR\left(T_2-T_1\right))/(1-n)=(2.5kg * 0.2968(kJ)/(kg* K)\left(450K-250K\right))/(1-1.4)=-371kJ

Notice that the answer units are kJ and it's negative because the work is done ON the system.

User Mustafa Aljaburi
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5.6k points
6 votes

Answer: -371kJ

Step-by-step explanation:

A frictionless piston–cylinder device contains 2.5 kg of nitrogen at 100 kPa and 250 K-example-1
User Nalin Nishant
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