Question

someone pls help thanks - Calculate the total energy in the 1.5x10^13 photons of gamma radiation having wavelength of 3.0x10^-12

Answer 1

Total energy is 9.932 × 10^-1 Joules

Step-by-step explanation:

Using the concept on energy of photons

Energy of a photon, E, is given by;

E = hf, where h is the plank's constant and f is the frequency of the radiation.

But, since frequency is given by dividing the velocity, c, by wavelength, λ,

Then; E = hc/λ

In this case; we are given more than one photons.

Therefore;

Energy = n × hc/λ , where n is the number of photons

Given;

n (the number of photons) = 1.5x10^13 photons

h (plank's constant) = 6.626× 10^-34 J/s

c (speed of light in vacuum) = 2.998 x 10^8 m/s

λ (wavelength of the radiation) = 3.0x10^-12 m

We can calculate energy;

Energy = (nhc)/λ ,

`Energy = ((1.5.10^(13))(6.626.10^(-34) J/s)(2.998.10^8 m/s))/(3.0.10^(-12) m)`

= 9.932 × 10^-1 Joules

Thus the total energy in the 1.5x10^13 photons is 9.932 × 10^-1 Joules