Answer:
a) 0.2713
b)Zombie Infection and Ragnarok, Ragnarok and UFO invasion.
Explanation:
We are given the following information in the question:
There is a 10% chance of a zombie infection. There is a 12% chance of Ragnarok . There is an 8% chance of a UFO invasion.
Thus, we can write:
P(A) = P(Zombie Infection) = 10% = 0.10
P(B) = P(Ragnarok) = 12% = 0.12
P(C) = P(UFO Invasion) = 8% = 0.08
It is given that all three events are independent.
a) P(an apocalypse of one sort or another)
![P(A \cup B \cup C) = P(A) + P(B) + P(C) + -P(A \cup B) - P{A \cup C) - P(B \cup C)](https://img.qammunity.org/2020/formulas/mathematics/college/8lyq16ldjd8wz6vtzfgbbpfrki4znbp5ri.png)
Since the events are independent
![P(A \cup B \cup C) \\\\=P(A) + P(B) + P(C) - (P(A)* P(B) + P(A)* P(C) + P(B)* P(C))\\\\=0.10 + 0.12 + 0.08 - (0.10* 0.12) - (0.10* 0.08) - (0.08* 0.12)\\\\= 0.2713](https://img.qammunity.org/2020/formulas/mathematics/college/ka3z8b36ydofsx688roxgn7ab3knc8kecn.png)
b)
![P(A \cap B) = P(A)* P(B) = 0.10* 0.12 = 0.012\\P(A \cap C) = P(A)* P(C) = 0.10* 0.08 = 0.008\\P(B \cap C) =P(B)* P(C) = 0.12* 0.08 = 0.0096](https://img.qammunity.org/2020/formulas/mathematics/college/rn9aup1fi5wr46doysfngg91u79c4w90a1.png)
Now, want a combination of apocalypse such that probability is greater than or equal to 0.009.
P( Combination ) > 0.009
Thus, the possible combination of apocalypse are:
Zombie Infection and Ragnarok
Ragnarok and UFO invasion.