Question

You kick a ball with a speed of 4 m/s at an angle of 10ﾟ. How far away does the ball land?

Answer 1

Answer: 0.55m



1. First find Vf
• 4 Sin(10)=0.7
•Vf= 0.7

2. Find time
•9.8=0.7/t
•9.8t=0.7
•t=0.07

3. Find distance
• 4 Cos(10)=d/0.14 < ————- double time
• d=0.55m

Answer 2

The ball goes 0.555 meter far away when kicked with a speed of 4 m/s at an angle of 10ﾟ.

Explanation :

From the given statements, we know

Initial Velocity (u) = 4 m/s

Angle at which it is projected (θ) = 10 degree

Let acceleration due to gravity (g) = 9.8 m/
`s^2`

Range = ?

Using the formula of Range, and substituting the values

Range=
`\frac{\mathrm{u}^(2) \sin 2 \theta}{\mathrm{g}}`

=
`(4^(2) \sin 2 * 10)/(9.8)`

=
`(16 * 0.34)/(9.8)` = 0.555 m