Answer:
Odds for and odd against the given event of rolling a fair die is
and
respectively.
Solution:
Need to find the odds for and odd against the event of rolling a fair die and getting 6, 2, 1
Number of possible outcomes of rolling a fair die = 6
Number of favorable outcome that is getting 6,2 or 1 = 3
Number of non favorable outcomes that is getting 5, 4 or 3 = 3
![\text { Odd for getting a } 6,2, \text { or } 1=\frac{\text { Number of favorable outcome }}{\text { Number of possible outcomes }}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v7u6f7z33ybf9etjotvm267y8zf45pj3wd.png)
![= (3)/(6) = (1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/69uiyp4o0rygruyfuwf44uwuu5tjp1d919.png)
Odd against getting a 6, 2 or 1 means odds for getting 5, 4 or 3
![\text { So, odd against getting a } 6,2, \text { or } 1=\frac{\text { Number of non favorable outcomes }}{\text { Number of possible outcomes }}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/96pilm2hw7fk0rmd3891genfu8l5myhkcl.png)
![= (3)/(6) = (1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/69uiyp4o0rygruyfuwf44uwuu5tjp1d919.png)
Hence odds for and odd against the given event of rolling a fair die is
and
respectively.