Question

The distance between two telephone poles is 36 m. When a 1.99 kg bird lands on the telephone wire midway between the poles, the wire sags 0.118 m. The acceleration of gravity is 9.8 m/s 2 . How much tension in the wire does the bird produce? Ignore the weight of the wire. Answer in units of N.

Answer 1

Answer:1501.86 N

Step-by-step explanation:

Given

Distance between Poles=36 m

Mass of bird (m)=1.99 kg

wire sag =0.118 m

angle made by wire with horizontal is given by

`tan\theta =(0.118)/(18)=0.0065`

`\theta =0.372^(\circ)`

Let
`T_1 and\ T_2` be the tensions in the wires

On resolving

`T_1\cos\theta =T_2\cos \theta`

thus
`T_1=T_2`

and
`2T_1\sin \theta =mg`

`2* T_1 * sin(0.372)=1.99* 9.8`

`T_1=1501.86 N=T_2`