Question

The Starship Enterprise is caught in a time warp and Spock is forced to use the primitive techniques of the 20th century to determine the specific heat capacity of an unknown mineral. The 120-g sample was heated to 92.6°C and placed into a calorimeter containing 82.9 g of water at 20.0°C. The heat capacity of the calorimeter was 15.3 J/K. The final temperature in the calorimeter was 24.8°C. What is the specific heat capacity (in J/g°C) of the mineral? Enter to 4 decimal places.

Answer 1

Answer:c=0.213 J/g/K

Step-by-step explanation:

Given

sample mass
`(m_s)=120 gm`

initial temperature of mineral
`(T_(im))=92.6`

mass of water
`(m_w)=82.9`

Water initial temperature
`(T_(iw))=20`

Heat capacity of calorimeter =15.3 J/k

Final Temperature is 24.8

let c be the specific heat of mineral

Heat released by mineral sample=heat absorbed by calorimeter and water

`120* c* (92.6-24.8)=82.9* 4.184* (24.8-20)+15.3* (24.8-20)`

`c* 67.8=14.486`

`c=0.213 J/g/K`