Question

Using the variable definitions​ above, compute the force exerted on a single​ leg, of a perfectly stationary​ platform, by waves moving at a velocity of 12 ​m/s. The waves are not accelerating at and the coefficients of drag and inertia are 0.73 and 0.34​, respectively. The cross sectional area of one leg is 879 msquared and the volume of a leg is 9813 mSuperscript nothingcubed. The density of the water is 1002 ​kg/mcubed. Compute the force exerted on the leg of the platform.

Answer 1

46292640.48 N

Step-by-step explanation:

a = Accelration of the water = 0

A = Cross sectional area =
`879\ m^2`

`\rho` = Density of water =
`1002\ kg/m^3`

u = Velocity of water = 12 m/s

V = Volume of body =
`9813\ m^3`

`C_d` = Drag coefficient = 0.73

`C_m` = Inertia coefficient = 0.34

`F=\rho C_mVa+(1)/(2)\rho C_dAu^2\\\Rightarrow F=1002* 0.34* 9813* 0+(1)/(2)* 1002* 0.73* 879* 12^2\\\Rightarrow F=46292640.48\ N`

The force exerted on the leg of the platform is 46292640.48 N