Question

Please, help.. (: P)

Answer 1

`y=-(3)/(5) +1.4`

Step-by-step explanation:

`y+1=-(3)/(5) (x-4)`

> What you do to one side, you do to the other. So subtract 1 from both sides to get y by itself to get it into the slope intercept formula:
`y=mx+b`

> Then distribute (multiply) the
`-(3)/(5)` to x and -4 to get
`-(3)/(5) x+2.4`

> Your new equation is
`y=-(3)/(5) +2.4-1`

> 2.4 and 1 are like terms so subtract 1 from 2.4 to get 1.4 which is the point that you plot on the graph.

> Since
`(3)/(5)` is negative, your line will go up 3 and down 5 using the
`(rise)/(run)` formula. Rise is vertical (y) and Run is horizontal (x).

Answer 2

The given equation is

`y+1=-(3)/(5) (x+4)`

The graph of this equation is line, because it's a linear equation.

First, we rewrite the given equation into a slope-intercept form

`y+1=-(3)/(5) (x+4)\\y=-(3)/(5)x-(12)/(5)-1\\ y=-(3)/(5)x-(17)/(5)`

Now, for
`x=0` we find
`y`

`y=-(3)/(5)(0)-(17)/(5)=-(17)/(5)`

Then, for
`y=0` we find
`x`

`0=-(3)/(5)x-(17)/(5)\\(17)/(5)=-(3)/(5)x\\x=-(17)/(3)`

So, the two points that we use to graph are
`(0,-(17)/(5))` and
`(-(17)/(3),0)`.

The graph is attached.