Question

In a game of darts, the dart thrower releases the dart directly at the center of the target (the "bull’s eye") with a speed of 13.0 m/s, and the dart strikes the wall, 0.23 m directly below the center of the target. How far from the wall, along the x-axis, was the dart released?

Answer 1

Answer:2.81 m

Step-by-step explanation:

Given

speed(u)=13 m/s

dart strikes 0.23 m below

i.e. vertical distance traveled by dart is 0.23 m

considering dart motion similar to Projectile

`h=ut+(at^2)/(2)`

`0.23=0+(9.8t^2)/(2)`

`t=0.216 s`

Horizontal distance travel by dart =u\times t

`=13* 0.216=2.81 m`