Question

Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. The length l of the bar obeys the following relation: l=1.0000+2.4×10−5T, where T is the number of degrees Celsius above room temperature. What is the change of the bar's length if the temperature is raised to 13.0 ∘C above room temperature?

Answer 1

ΔL =0. 000312 m

Step-by-step explanation:

Given that

At room temperature ( T = 25 ∘C) ,L= 1 m

`L=1+2.4* 10^(-5)T`

So the length at 13.0 ∘C above room temperature

`L=1+2.4* 10^(-5)T`

`L=1+2.4* 10^(-5)* 13`

L=1.000312 m

So the change in length

ΔL = 1.000312 - 1.0000 m

ΔL =0. 000312 m