Question

The value pie/2 is a solution for the equation 2sin^2x-sinx-1=0

true or false

Answer 1

Yes,
`(\pi )/(2)` is a solution

Explanation:

Recall that
`sin((\pi )/(2))=1`. By replacing
`(\pi )/(2)` in the given trigonometric equation, we get 0 (zero) as a result, so this value is a solution:

`2*(sin((\pi )/(2) ))^2-sin((\pi )/(2))-1= 2*(1)^2-1-1=2-2=0`