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Ask Your Teacher Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example, one study found that drivers of trains had a higher incidence of blood cancer than other railway workers, possibly due to long exposure to mechanical devices in the train engine cab. Consider a magnetic field of magnitude 0.00100 T, oscillating sinusoidally at 69.5 Hz. If the diameter of a red blood cell is 6.20 µm, determine the maximum emf that can be generated around the perimeter of a cell in this field.

User Thegeko
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5 votes

Answer:


1.32*10^(-11)

Step-by-step explanation:

Magnetic field
B=B_(max)sin(wt)

But
w=2f\pi and f is given as 69.5Hz
B_(max) is 0.00100T

Flux through cell,
\theta=B*Area of cell

Area of cell=
\pi R^{2) and radius of cell is 6.2µm/2=3.1µm converted to mm it's
3.1*10^(-6)

Change in magnetic flux=
\frac {d\theta}{dt}=\frac {d}{dt}sin wt*\pi R^(2)B_(max)


\frac {d\theta}{dt}=w cos wt*\pi R^(2)B_(max)

magnitude of induced emf
\epsilon= w cos wt*\pi R^(2)B_(max) where
wB_(max)\pi R^(2) gives maximum value of induced emf


\epsilon_(max)=wB_(max)\pi R^(2)

Since
w=2f\pi=2*69.5* \pi,
B_(max)=0.00100T and R=
3.1*10^(-6)


\epsilon_(max)=2*69.5* \pi *0.00100*\pi *(3.1*10^(-6))^(2)

=
1.31837*10^(-11)

Rounded off to 2 decimal places, max emf=
1.32*10^(-11)

User JacksonHaenchen
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