Question

A baseball is hit with an initial velocity of 44 ft/s at a height 4ft above the ground. Determine each of the following. the maximum height attained by the baseball. how long it takes for the baseball to attain its maximum height how long it takes for the baseball to hit the ground

Answer 1

Explanation:

Given

initial Velocity(u)=44 ft/s

ball initial height =4 ft

as launch angle is not given so considering ball is hit vertically upward

`v^2-u^2=2as`

where u =initial velocity

v=final velocity

a=acceleration

s=distance traveled

`0-44^2=2* (-32.2)\cdot s`

`s=(44^2)/(2* 32.2)=30.06 ft`

time taken to reach 30.06 ft

`v=u+at`

`0=44-32.2* t`

`t=1.36 s`

total distance to reach ground=4+30.06 ft=34.06 ft

`s=ut+(at^2)/(2)`

`34.06=(32.2* t^2)/(2)`

`t^2=2.115`

t=1.45 s