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1 vote
Identify the distance, to the nearest tenth, between C(−7,−9) and J(6,2).

User Spats
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1 Answer

1 vote

Answer:

The answer is 17.02, to the nearest tenth is 17.

Explanation:

Under the radical, that us take the square root of the following sum:

(Jx - Cx )^2 + (Jy - Cy)^2

Substitute in the values:

(6 - (-7))^2 + (2 - (-9))^2 =

This becomes:

(6+7)^2 + (2 + 9)^2 =

13^2 + 11^2 =

169 + 121 =

Sqrt 290 =

17.029 = To the nearest 10th is 17

User Tiagojdferreira
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