Question

The magnetic field at the center of a 0.50-cm-diameter loop is 2.9 mT . Part A What is the current in the loop? Express your answer in amperes. I I = nothing A SubmitRequest Answer Part B A long straight wire carries the same current you found in part a. At what distance from the wire is the magnetic field 2.9 mT ? Express your answer in meters. L L = nothing m SubmitRequest Answer Provide Feedback Next

Answer 1

A)I=11.35 A

B)R=0.079 cm

Step-by-step explanation:

Given that

For loop:

d= 0.5 cm ,r=0.25 cm

B=2.9 mT

A)

We know that magnetic filed in loop given as

`B=(\mu _oI)/(2 r)` -----1

Now by putting the values

`2.9* 10^(-3)=(4\pi * 10^(-7)I)/(2 * 0.25* 10^(-2))`

`I=\frac {2.9* 10^(-3)* {2 * 0.25* 10^(-2)}}{4\pi * 10^(-7)}\ A`

I=11.35 A

B)

Magnetic filed for wire given as

`B=(\mu _oI)/(2\pi R)` ----2

Given that B and I is same so we can say that

Form equation 1 and 2

π R= r

`R=(r)/(\pi)`

`R=(0.25)/(\pi)`

R=0.079 cm