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At t= 10 s, a particle is moving from left to right with a speed of 5.0 m/s. At t=20 s, the particle is moving right to left with a speed of 8.0 m/s. Assuming the particle's acceleration is constant, determine (a) its acceleration,

(b)its initial velocity, and
(c) the instant when its velocity is zero.

User Tal Angel
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1 Answer

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Answer

given,

at time t = 10 s moving from left to right speed of particle = 5 m/s

at t = 20 s moving from right to left speed of particle is = 8 m/s

a) acceleration


a = (\Delta V)/(\Delta t)


a = (-8-(5))/(20-10)

a = -1.3 m/s²

b) using equation of motion

v = u + at

5 = u - 1.3 × 10

u = 5 + 13

u = 18 m/s

c) v = u + at

0 = 18 - 1.3t


t = (18)/(1.30)

t = 13.85 s

User Sam Sabin
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