Question

If 16.5g of c6h14o2 are reacted vwith .499 mol of o2. How many moles of co2 should be produced

Answer 1

1.96 mole

Step-by-step explanation:

Thinking process:

First, we have to write a balanced chemical equation:

`C_(6)H_(14)O_(2) + 17O_(2) = 14CO_(2) + 12H_(2)O`

the mass of C6H14O2 = 16.5

the molar mass of C6H14O2 = 118.0

the number of moles of C6H14O2 =
`(16.5)/(118) \\ =0.140 mole`

the number of moles produced = 14 × number of moles of C6H14O2

= 14 × 0.140 mole

= 1.96 mole

Answer 2

moles of carbon dioxide produced are 410.9 mol.

Step-by-step explanation:

Given data:

Mass of C₆H₁₄O₂ = 16.5 g

Moles of O₂ = 499 mol

Moles of CO₂ = ?

First of all we will write the balance chemical equation.

2C₆H₁₄O₂ + 17O₂ → 14CO₂ + 12H₂O

moles of C₆H₁₄O₂ = mass × molar mass

moles of C₆H₁₄O₂ = 16.5 g × 118 g/mol

moles of C₆H₁₄O₂ = 1947 mol

Now we compare the moles of CO₂ with moles of O₂ and C₆H₁₄O₂ from balance chemical equation.

O₂ : CO₂

17 : 14

499 : 14/17× 499 = 410.9 moles

C₆H₁₄O₂ : CO₂

2 : 14

1947 : 14/2× 1947 = 13629 moles

Oxygen will be limiting reactant so moles of carbon dioxide produced are 410.9 mol.