Question

If an object of 47kg and it is moved 27 meters in 60 seconds how much power is used

Answer 1

207 W

Step-by-step explanation:

I assumed here that the object is moved vertically. If that is the case, the work done on the object is equal to its change in gravitational potential energy:

`W=\Delta U = mg \Delta h`

where

m = 47 kg is the mass of the object

g = 9.8 m/s^2 is the acceleration of gravity

`\Delta h = 27 m` is the change in height

Substituting,

`W=(47)(9.8)(27)=12436 J`

Now we can calculate the power used, which is given by

`P=(W)/(t)`

where t = 60 s is the time taken. Substituting,

`P=(12436)/(60)=207 W`