Answer:
54.1 m at
(south of east)
Step-by-step explanation:
Displacement is a vector connecting the initial position with the final position of motion.
In this problem, the motion consists of two parts:
- A first movement 25 m east
- A second movement 48 m south
We can therefore write a vector representing the displacement as
![d=(25i-48j)](https://img.qammunity.org/2020/formulas/physics/middle-school/fwn51q8m8u2qocicerr2r2ur7k2a53kya6.png)
where i is the unit vector indicating the east direction and j the unit vector indicating the north direction.
Therefore, the total displacement is just the magnitude of this vector:
![d=√(25^2+(-48)^2)=54.1 m](https://img.qammunity.org/2020/formulas/physics/middle-school/iw7rjos4plw6rn5kdqna9brq7u7dnzm26p.png)
And the direction is given by
![\theta=tan^(-1)((d_y)/(d_x))=tan^(-1) ((-48)/(25))=-62.5^(\circ)](https://img.qammunity.org/2020/formulas/physics/middle-school/oud5pgfiy2a3n0zmguuwlyc9n56znqer6x.png)