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A wall clock has a minute hand with a length of 0.53 m and an hour hand with a length of 0.26 m. Take the center of the clock as the origin, and use a Cartesian coordinate system with the positive x axis pointing to 3 o'clock and the positive y axis pointing to 12 o'clock. What is the magnitude of the acceleration of the tip of the minute hand of the clock?

User Megloff
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1 Answer

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Answer:

a =1.61 × 10⁻⁶ m/s²

Step-by-step explanation:

given,

length of minute hand = 0.53 m

length of hour hand = 0.26 m

the time taken by the minute hand to complete one revolution is T=3600 s

the angular frequency is


\omega =(2\pi )/(T)


\omega =(2\pi )/(3600)


\omega=0.001745 rad/sec

the acceleration is


a = r \omega^2


a = (0.53) * (0.001745)^2

a =1.61 × 10⁻⁶ m/s²

User Lucas Van Dongen
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