9.
By the Segment Addition Postulate, SAP, we have
XY + YZ = XZ
so
YZ = XZ - XY = 5 cm - 2 cm = 3 cm
10.
M is the midpoint of XZ=5 cm so
XM = 5 cm / 2 = 2.5 cm
11.
XY + YM = XM
YM = XM - XY = 2.5 cm - 2 cm = 0.5 cm
12.
The midpoint is just the average of the coordinate A(-3,2), B(5,-4)
![M = (A+B)/2 = \left( (-3 + 5)/(2), (2 + -4)/(2) \right)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k4egpqvpcncrgdefdtttihk6q1rqfx1i5k.png)
Answer: M is (1,-1)
You'll have to plot it yourself.
13.
For distances we calculate hypotenuses of a right triangle using the distnace formula or the Pythagorean Theorem.
![AB^2 =(5 - -3)^2 + (-4 - 2)^2 = 8^2 + 6^2 = 100](https://img.qammunity.org/2020/formulas/mathematics/middle-school/og702zhz01kpofgo534jn0bwlyhreni9kr.png)
Answer: AB=10
M is the midpoint of AB so
Answer: AM=MB=5
14.
B is the midpoint of AC. We have A(-3,2), B(5,-4)
B = (A+C)/2
2B = A + C
C = 2B - A
C = ( 2(5) - -3, 2(-4) - 2 ) = (13, -10)
Check the midpoint of AC:
(A+C)/2 = ( (-3 + 13)/2, (2 + -10)/2 ) = (5, -4) = B, good
Answer: C is (13, -10)
Again I'll leave the plotting to you.