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What were the dimensions of the original photo?

O4 inches by 4 inches
O 6 inches by 6 inches
10 inches by 10 inches
12 inches by 12 inches

What were the dimensions of the original photo? O4 inches by 4 inches O 6 inches by-example-1

2 Answers

5 votes

Answer: B

Explanation:

User Iqbal Fauzi
by
7.1k points
3 votes

Answer: second option.

Explanation:

Given the following equation:


(x+10)^2=256

You need to find the value of "x" in order to find the side measure of the original square photo.

Knowing that:


(a+b)^2=a^2+2ab+b^2

You can expand the equation:


(x+10)^2=256\\\\x^2+2(x)(10)+10^2=256\\\\x^2+20x+100=256

The next step is to subtract 256 from both sides of the equation:


x^2+20x+100-256=256-256\\\\x^2+20x-156=0

Now you can factor the quadratic equation. Find two numbers whose sum is 20 and whose product is -156. These are 26 and 6:


(x+26)(x-6)=0\\\\x_1=-26\\\\x_2=6

Choose the positive value.

Therefore, the dimensions of the original square photo were:


6\ inches\ by\ 6\ inches

User Pramod Sivadas
by
6.6k points
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