Question

3b-14/3b = 5b+2/3b
b= ?

Answer 1

A) -8

Explanation:

You have to make the whole equation equal to zero. so rewrite the equation and equal it to zero. Write all numerators above the common denominator

3(b-5)+1-(5b+2) over 3b equal zero

Then remove parentheses

3b-15+1-5b-2 over 3b equals zero

Then collect the like terms

Calculate

-2b-16 over 3b equals zero

Then set the numerator equal to zero

-2b-16=0

Then move constant to the right

-2b=16

Then divide both sides by -2

b=-8

Answer 2

First of all, observe that all fractions exist as long as b is not zero.

Multiply both numerator and denominator of the first fraction by 3:

`(3b-15)/(3b)+(1)/(3b)=(5b+2)/(3b)`

Now all fractions have the same denominator. Under the assumption that b is not zero, multiply both sides by 3b:

`3b-15+1=5b+2 \iff 3b-14=5b+2`

Subtract 3b from both sides:

`-14=2b+2`

Subtract 2 from both sides:

`-16=2b`

Divide both sides by 2:

`b=-8`