Answer:
The given values are:
240,272,280,285,295,285,300,290,310,305,285,305
with n=12.
The sorted set of numbers is:
240 272 280 285 285 285 290 295 300 305 305 310
minimum = 240
Q1 = 282.5
median = 287.5
Q3 = 302.5
maximum = 310
the five-number summary is (240,282.5,287.5,302.5,310)
The interquartile range (IQR) = Q3-Q1 = 20
We proceed to calculate the lower and upper fences.
Lower fence = Q1-1.5(IQR)=252.5
Upper fence = Q3+1.5(IQR)=332.5
Since 240 falls below the lower fence (252.5), we conclude that 240 is an outlier, it should be eliminated from the data and the above calculations repeated.
272 280 285 285 285 290 295 300 305 305 310
and five-number summary:
272.0 285.0 290.0 302.5 310.0
1.5IQR = (302.5-285) = 26.25
and the fences are:
Lower fence = 285-26.25 = 258.75
Upper fence = 302.5 + 26.25 = 328.75
Since this time around, no data falls outside of the fences
(check: min=272>258.75, max=310<328.75)
We conclude that there are no more outliers in this trimmed list
272 280 285 285 285 290 295 300 305 305 310