A. The outcome on the dice are independent hence yes
B. P(6 on green die and 4 on red die) = 1 / 36
c. P(4 on green die and 6 on red die) = 1 / 36
d. P((6 on green die and 4 on red die) or (4 on green die and 6 on red die)) = 1 / 18
How to solve for the probability
b. P(6 on green die and 4 on red die)
This is a fair die. Each outcome on the die only has 1 / 6 probability
hence
P(6 on green die) = 1 / 6
P(4 on red die) = 1 / 6
P(6 on green die and 4 on red die) = 1 / 6 * 1 / 6 = 1/36
c. P(4 on green die and 6 on red die)
just as we have done above
each still has 1 / 6 probability of happening
= 1 / 6 * 1 / 6
= 1 / 36
d. P((6 on green die and 4 on red die) or (4 on green die and 6 on red die)).
This is P((6 on green die and 4 on red die) + (4 on green die and 6 on red die)).
P((6 on green die and 4 on red die) = 1 / 36
p(4 on green die and 6 on red die) = 1 / 36
= 1 / 36 + 1 / 36
= 2 / 36
= 1 / 18