Question

A 500-g squirrel with a surface area of 1020 square centimeters falls from a 5.5-meter tall tree to the ground. What is its terminal velocity? (Use the drag coefficient of a horizontal skydiver, and assume that the density of the air is 1.16 kg/m33).

Answer 1

Terminal velocity will be 9.10 m/sec

Step-by-step explanation:

We have given mass of squirrel m = 500 gram = 0.5 kg

Area
`A=1020cm^2=0.1020m^2`

Density is given as
`\rho =1.16kg/m^3`

We have to find the terminal velocity

Terminal velocity is given by
`v=\sqrt{(2mg)/(\rho CA)}`, here m is mass, g is acceleration due to gravity , C is drag coefficient,
`\rho` is density

Here value of drag coefficient C = 1

So terminal velocity
`v=\sqrt{(2* 0.500* 9.81)/(1.16* 1* 0.1020)}=9.10m/sec`