Question

A sample of rock from California contains 1.116g of iron and 0.48 g of oxygen.

Determine the percent composition of both element in the sample.

Answer 1

`\%\ Composition\ of\ iron=69.92\ %`

`\%\ Composition\ of\ oxygen=30.08\ \%`

Step-by-step explanation:

Percent composition is percentage by the mass of element present in the compound.

Given , Mass of iron = 1.116 g

Mass of oxygen = 0.48 g

Total mass of the rock = 1.596 g

`\%\ Composition\ of\ iron=(Mass_(iron))/(Total\ mass)* 100`

`\%\ Composition\ of\ iron=(1.116)/(1.596)* 100`

`\%\ Composition\ of\ iron=(111.6)/(1.596)`

`\%\ Composition\ of\ iron=69.92\ \%`

`\%\ Composition\ of\ oxygen=(Mass_(oxygen))/(Total\ mass)* 100`

`\%\ Composition\ of\ oxygen=(0.48)/(1.596)* 100`

`\%\ Composition\ of\ oxygen=(48)/(1.596)`

`\%\ Composition\ of\ oxygen=30.08\ \%`