Question

A 86.6-kg man is standing on a frictionless ice surface when he throws a 2.40-kg book horizontally at a speed of 10.9 m/s. With what speed does the man move across the ice as a result? Give your answer in m/s, and be sure to use three significant figures in your answer.

Answer 1

The speed of the man is 0.302m/s in the opposite direction.

Step-by-step explanation:

We need to apply the theorem of linear momentum:

`m1*vo1+m2*vo2=m1*vf1+m2*vf2`

The instant before the man throws the book the velocity is zero:

`86.6kg*(0)+2.40kg(0)=86.6kg*vf1+2.40kg*(10.9m/s)\\\\vf1=(-2.40kg*(10.9m/s))/(86.6kg)\\vf1=-0.302m/s`