Answer:
4.17 m/s
Step-by-step explanation:
To solve this problem, let's start by analyzing the vertical motion of the pea.
The initial vertical velocity of the pea is

Now we can solve the problem by applying the suvat equation:

where
is the vertical velocity when the pea hits the ceiling
is the acceleration of gravity
s = 1.90 is the distance from the ceiling
Solving for
,

Instead, the horizontal velocity remains constant during the whole motion, and it is given by

Therefore, the speed of the pea when it hits the ceiling is
