Answer:
a)
= -30 m/s
b)
= 30 m/s
Step-by-step explanation:
a)
Consider the car A travel at a velocity of
= 90 km/h and the car B travel at the velocity of
= 120 km/h. As the velocity of the car B is greater than the car A, So it cross the car A. Consider The velocity of car A relative to car B is
and it is equal to the velocity of car A minus the velocity of car B.
=
-
![v_(B)](https://img.qammunity.org/2020/formulas/physics/college/4yr2wi8mg7mm8v77ha0wqrw2qeu5s5rbio.png)
= 90 - 120
= -30 m/s
b)
Consider The velocity of car B relative to car A is
and it is equal to the velocity of car B minus the velocity of car A.
=
-
![v_(A)](https://img.qammunity.org/2020/formulas/physics/college/c6l3ona7n4bkat0710vrq2hq537fw7vaa7.png)
= 120 - 90
= 30 m/s