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A train starts from rest and accelerates uniformly until it has traveled 2.1 km and acquired a forward velocity of The train then moves at a constant velocity of for 400 s. The train then slows down uniformly at until it is brought to a halt. The distance traveled by the train while slowing down is closest to A train starts from rest and accelerates uniformly until it has traveled 2.1 km and acquired a forward velocity of The train then moves at a constant velocity of for 400 s. The train then slows down uniformly at until it is brought to a halt. The distance traveled by the train while slowing down is closest to 3.8 km. 4.2 km. 3.6 km. 4.4 km. 4.0 km.

User Masi
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1 Answer

2 votes

Answer:

4.4 km

Step-by-step explanation:

t = Time taken

u = Initial velocity = 24 m/s (Assumed)

v = Final velocity

s = Displacement

a = Acceleration = -0.065 m/s² (Assumed)

Distance = Speed × Time


\text{Distance}=24* 400=9600\ m

The train travels for 9600 m.


v=u+at\\\Rightarrow 0=24-0.065t\\\Rightarrow t=(-24)/(-0.065)=369.23\ s


s=ut+(1)/(2)at^2\\\Rightarrow s=24* 369.23+(1)/(2)* -0.065* 369.23^2\\\Rightarrow s=4430.76\ m

The Distance the train traveled when it slowed down is 4.4 km

User Onepan
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