Question

avitational force and the electrostatic force act on the particle, which moves on a horizontal straight line without rotating. The electric potential at A is 36.0 V greater than that at B; in other words, VA - VB = 36.0 V. What is the translational speed of the particle at point A?

Answer 1

`V={3.5* 10^(5)}\ m/s`

Step-by-step explanation:

Given that

VA - VB = 36.0 V

If we assume that ,the particle is electron.

For electron

The mass of electron

`m=9.1* 10^(-31)\ kg`

The charge on electron

`q=1.6* 10^(-19)\ C`

q( VA - VB) = 1/2 m V² (energy conservation)

`1.6* 10^(-19)* 36=(1)/(2)* 9.1* 10^(-31)V^2`

`(3.2* 10^(-19)* 36)/(9.1* 10^(-31))\ = V^2`

`V=\sqrt{1.265* 10^(13)}\ m/s`

`V={3.5* 10^(5)}\ m/s`