For this case, we propose a rule of three for each amount. Then we will add 20% and see if it is less than or equal to $60, if that is true then Clay can pay the tip of 20%:
$ 48.53 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
![x = \frac {20 * 48.53} {100}\\x = 11.6472](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x9ooh535ugghr5sezda7mldsuenrp2wqcw.png)
So, we have:
![48.53 + 11.6472 =\\60.1772](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6arsqss25pmkvlt1thrtfqke56lm9dr1ai.png)
With this bill Clay could not leave a 20% tip.
$ 49.75 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
![x = \frac {20 * 49.75} {100}\\x = 9.95](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rxkn2z0ry2mz44tg3bl66ky88f730x562o.png)
So, we have:
![49.75 + 9.95 =\\59.7 <60](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qnumuevs266dx55yelwaami8qtz5bzr2ni.png)
With this bill Clay could leave a 20% tip.
$ 54.99 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
![x = \frac {20 * 54.99} {100}\\x = 10,998](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1trtphnxch8haekdnh9ltzjr22trxusmw3.png)
So, we have:
![54.99 + 10.998 =\\65.988](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pn45r03a3hp5vgopoqk7w8jcz5bqs2bfez.png)
With this bill Clay could not leave a 20% tip.
$ 61.60 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
![x = \frac {20 * 61.60} {100}\\x = 12.32](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wy6epoa28galu1i4jhqrpplpe8flmjcfbm.png)
So, we have:
![61.60 + 12.32 =\\73.92](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dppk3zhky4i4f0rxo7otq5ikorokxyq5lv.png)
With this bill Clay could not leave a 20% tip.
$ 58.80 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
![x = \frac {58.80 * 20} {100}\\x = 11.76](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h315zd36k837jwveol1vpyjrvcj2tojmi9.png)
So, we have:
![58.80 + 11.76 = 70.56](https://img.qammunity.org/2020/formulas/mathematics/middle-school/39tq2he6yag49mvv0frbai48ckjxp28an2.png)
With this bill Clay could not leave a 20% tip.
$ 50 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
![x = \frac {50 * 20} {100}\\x = 10](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z9enwchibj97ipva0h8kq6fx4s4b5jh89d.png)
So, we have:
![50 + 10 = 60](https://img.qammunity.org/2020/formulas/mathematics/middle-school/suhsx69l1ot4itm3tasmtyzkhvoaqc1e2z.png)
With this bill Clay could leave a 20% tip.
So, I could only tip with the options B y F
ANswer:
Option B y F