Question

A car moving at 10.0 m/s encounters a bump that has a circular cross-section with a radius of 30.0 m. What is the normal force exerted by the seat of the car on a 60.0-kg passenger when the car is at the top of the bump?

A) 200 N
B) 389 N
C) 789 N
D) 589 N

Answer 1

option B

Step-by-step explanation:

given.

car is moving at = 10 m/s

bump of radius = 30 m

normal force = ?

mass of the passenger = 60 kg

m × g = 60 × 9.81 N

normal force acting

=
`mg - (mv^2)/(R)`

=
`60* 9.81 - (60* 10^2)/(30)`

=388.6 N

the normal force acting is equal to 389 N

hence, the correct answer is option B

Answer 2

force at the top will be 388 N which is nearly equal to 389

option (b) is correct

Step-by-step explanation:

We have given velocity of the moving car v = 10 m/sec

Radius of the circular section r = 30 m

Mass of the passenger m = 60 kg

Acceleration due to gravity
`g=9.8m/sec^2`

At the top normal force is given by
`noraml\ force=mg-(mv^2)/(r)`

So force at top will be
`F=60* 9.8-(60* 10^2)/(30)=388N`

So force at the top will be 388 N which is nearly equal to 389

So option (b) is correct