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A chemist creates a solution that contains the following ingredients and quantities

5 cups of potassium
5 cups of water
10 cups of sodium
10 cups of magnesium
20 cups of Silver Oxide
How much Silver oxide water and potassium would be in 1 cup of the solution

User Sam Cromer
by
8.4k points

2 Answers

7 votes

Answer:

2/5 cups of silver oxide

1/10 cups of water

1/10 cups of potassium

Explanation:

5+ 5 + 10 + 10+ 20 = 50

there are 50 total cups

now we must find the number to divide 50 by to get the 1 cup that we need

50 / 50 = 1

Now that we know what to divide by to get the quantities for 1 cup of solution, time to get the quantities

there are 20 cups of Silver oxide

20 / 50 = 2/5 cups

there are 5 cups of water

5 / 50 = 1/10 cups

there are 5 cups of potassium

5 / 50 = 1/10 cups

User Kaherdin
by
8.5k points
11 votes

it is 17

Explanation:

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User Sany Liew
by
8.6k points

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