Question

A 3.50 ÎĽf capacitor has a charge with a magnitude of 4.50 ÎĽc on each parallel plate. Find the potential difference between the plates.

Answer 1

Answer:
`7.77(10)^(-13) V`

Step-by-step explanation:

The capacitance
`C` is defined as the relationship between the electric charge of each conductor and the potential difference between them. That is, it is the capacity of a device to store electrical charge.

Mathematically it is defined as:

`C=(Q)/(V)`

Where:

`C=3.50 pF=3.50(10)^(-12) F` is the capacitance value of a capacitor.

`Q=4.50 C` is the electric charge of the conductor

`V` is the electric potential to which the conductor is located, measured in Volt.

Isolating
`V`:

`V=(Q)/(C)`

`V=(4.50 C)/(3.50(10)^(-12) F)`

Finally:

`V=7.77(10)^(-13) V`