Question

What is the overall enthalpy of reaction for the equation shown below?

3H^2 g + O^3 g > 3H^2O g

Answer 1

-867.7

Step-by-step explanation:

Answer 2

Δ
`rH=-869kJ/mol`

Step-by-step explanation:

Hello, for this chemical reaction, the overall enthalpy of reaction is defined by:

Δ
`rH=3H_{f_(H_2O)}-H_{f_(O_3)}`

Since the enthalpy of formation of water is 0 as long as it is a pure element. Now, applying the formula with the proper values (extracted from the NIST database), we get:

Δ
`rH=3*(-242kJ/mol)-(143kJ/mol)`

Δ
`rH=-869kJ/mol`

Best regards.