Answer:
The volume of steam produced is 72 ml
Step-by-step explanation:
We need to first write the balanced equation for the reaction between Ammonia and oxygen.
The balanced equation is;
4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(g)
Remember the Gay-lussac's law of combining gases;
At constant pressure and temperature, gases react bearing a simple ratio to one another.
In this case;
From the equation the ratio of the reactants and products will be;
4V: 5V: 4V: 6V
We are given, 50 ml of NH₃ and 60 ml of Oxygen
Assuming all the volume of oxygen (60 ml) was completely consumed, then we can use the simple ratios to find the volume of the other reactant consumed and the volume of reactants.
Volume of O₂ = 60 ml (completely consumed)
The volume of Ammonia = ( 60/5)× 4
= 48 ml
Therefore; 48 ml of NH₃ was consumed and 2 ml NH₃ remained
The volume of H₂O (steam produced)
The ratio of O₂ to H₂O is 5: 6
Therefore;
Volume of steam = (60/5) × 6
= 72 ml
Therefore; the volume of steam produced is 72 ml