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Object A attracts object B with a gravitational force of 5 newtons from a given distance. If the distance between the two objects is reduced in

half, what will be the changed force of attraction between them?

User Zshanabek
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2 Answers

0 votes

Answer:

Four times higher

Step-by-step explanation:

F- G (m1 x m2)/ r^2

if r 1 = 2 and r 2 = 1 therefore F = G (m1 x m2)/ 1^2 is 4 times higher than

2^2 since G and m1 and m2 remained the same

User PDug
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5.5k points
7 votes

answer is D. 20 newtons for plato, got 100 on the test :)

User Neeraj Verma
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