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Tangent slope of 4x^2+2x when x=-2

User Jakub Zak
by
7.4k points

1 Answer

4 votes

Answer:

-14

Explanation:

f(x) = 4x² + 2x

Take the first derivative:

f'(x) = 8x + 2

Evaluate at x = -2:

f'(-2) = 8(-2) + 2

f'(-2) = -14

The tangent slope is -14.

User Blacktiger
by
8.7k points

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